naughtyG
Well-Known Member
So where's my beer?
It's in the cooler m8 :eusa_dance:
So where's my beer?
It's in the cooler m8 :eusa_dance:
Damm my ist empty :bang head:It's in the cooler m8 :eusa_dance:
Cant help ya :rofl_200:Did someone say "Beer".... I want some!!!!!!
I was wondering what you all thought about the best front tire for my drag bike project. I think for now I am going to use the stock 85 front wheel/rim and was planning on running a 100/90-18 tire. I think that equates to a 3.25/4.00-18 tire (or tyre depending where you live).
Here are some options I found on eBay:
KENDA Challenger Tire K-657F 100-90-18 = $55
DUNLOP D404 SIZE 100/90-18 FRONT TIRE = $73
Metzeler Marathon ME880 100/90/18 H = $130
Bridgestone Battlax BT-45V 100/90 V-18 = $93
I'm sure there are more (cheng shin), just wanted to see what you all thought and if you have any imput. Of course I want something lightweight, but I also don't want it flying apart on me.
Thanks,
Jeff
Jeff,Most drag bikes use a very small and light wieght front end and wheel off of a small bike.
Lankee, since you like my numbers and calculations so much, I decided to model up a tire in my CAD program and calculated the numbers with 2 different densities. Now I know the rubber densities won't be twice as dense, and the changes are more in the thickness of the tires, but this will at leas show you how the rotational inertia will change with a 9.3 lb tire vs. a 4.6 lb tire. These are just a little lighter than a stock tire and the tire I purchased. The 'X' axis would be the axil.
LIGHT TIRE
VOLUME = 8.4822438e+06 MM^3
SURFACE AREA = 2.7036586e+06 MM^2
DENSITY = 2.5000000e-07 KILOGRAM / MM^3
MASS = 2.1205609e+00 KILOGRAM
CENTER OF GRAVITY with respect to _TIRE_TEST coordinate frame:
X Y Z 0.0000000e+00 0.0000000e+00 0.0000000e+00 MM
INERTIA with respect to _TIRE_TEST coordinate frame: (KILOGRAM * MM^2)
INERTIA TENSOR:
Ixx Ixy Ixz 5.3283652e+05 0.0000000e+00 0.0000000e+00
Iyx Iyy Iyz 0.0000000e+00 2.7832740e+05 0.0000000e+00
Izx Izy Izz 0.0000000e+00 0.0000000e+00 2.7832753e+05
INERTIA at CENTER OF GRAVITY with respect to _TIRE_TEST coordinate frame: (KILOGRAM * MM^2)
INERTIA TENSOR:
Ixx Ixy Ixz 5.3283652e+05 0.0000000e+00 0.0000000e+00
Iyx Iyy Iyz 0.0000000e+00 2.7832740e+05 0.0000000e+00
Izx Izy Izz 0.0000000e+00 0.0000000e+00 2.7832753e+05
PRINCIPAL MOMENTS OF INERTIA: (KILOGRAM * MM^2)
I1 I2 I3 2.7832726e+05 2.7832767e+05 5.3283652e+05
STOCK TIRE
VOLUME = 8.4822438e+06 MM^3
SURFACE AREA = 2.7036586e+06 MM^2
DENSITY = 5.0000000e-07 KILOGRAM / MM^3
MASS = 4.2411219e+00 KILOGRAM
CENTER OF GRAVITY with respect to _TIRE_TEST coordinate frame:
X Y Z 0.0000000e+00 0.0000000e+00 0.0000000e+00 MM
INERTIA with respect to _TIRE_TEST coordinate frame: (KILOGRAM * MM^2)
INERTIA TENSOR:
Ixx Ixy Ixz 1.0656730e+06 0.0000000e+00 0.0000000e+00
Iyx Iyy Iyz 0.0000000e+00 5.5665481e+05 0.0000000e+00
Izx Izy Izz 0.0000000e+00 0.0000000e+00 5.5665506e+05
INERTIA at CENTER OF GRAVITY with respect to _TIRE_TEST coordinate frame: (KILOGRAM * MM^2)
INERTIA TENSOR:
Ixx Ixy Ixz 1.0656730e+06 0.0000000e+00 0.0000000e+00
Iyx Iyy Iyz 0.0000000e+00 5.5665481e+05 0.0000000e+00
Izx Izy Izz 0.0000000e+00 0.0000000e+00 5.5665506e+05
PRINCIPAL MOMENTS OF INERTIA: (KILOGRAM * MM^2)
I1 I2 I3 5.5665452e+05 5.5665535e+05 1.0656730e+06
I'm sure you know all about rotational inertia and some people claim that 1lb of rotational mass ='s 5 to 7 lbs of static weight, so by me saving anywhere from 5 to 7 lbs of rotational mass, that ='s quite a few burritos.
If anyone else wants to explain this more feel free, I am digging through some old info and will try to correlate this back to a HP savings, but I might give up before I do.
Jeff
Lankee, since you like my numbers and calculations so much, I decided to model up a tire in my CAD program and calculated the numbers with 2 different densities. Now I know the rubber densities won't be twice as dense, and the changes are more in the thickness of the tires, but this will at leas show you how the rotational inertia will change with a 9.3 lb tire vs. a 4.6 lb tire. These are just a little lighter than a stock tire and the tire I purchased. The 'X' axis would be the axil.
LIGHT TIRE
VOLUME = 8.4822438e+06 MM^3
SURFACE AREA = 2.7036586e+06 MM^2
DENSITY = 2.5000000e-07 KILOGRAM / MM^3
MASS = 2.1205609e+00 KILOGRAM
CENTER OF GRAVITY with respect to _TIRE_TEST coordinate frame:
X Y Z 0.0000000e+00 0.0000000e+00 0.0000000e+00 MM
INERTIA with respect to _TIRE_TEST coordinate frame: (KILOGRAM * MM^2)
INERTIA TENSOR:
Ixx Ixy Ixz 5.3283652e+05 0.0000000e+00 0.0000000e+00
Iyx Iyy Iyz 0.0000000e+00 2.7832740e+05 0.0000000e+00
Izx Izy Izz 0.0000000e+00 0.0000000e+00 2.7832753e+05
INERTIA at CENTER OF GRAVITY with respect to _TIRE_TEST coordinate frame: (KILOGRAM * MM^2)
INERTIA TENSOR:
Ixx Ixy Ixz 5.3283652e+05 0.0000000e+00 0.0000000e+00
Iyx Iyy Iyz 0.0000000e+00 2.7832740e+05 0.0000000e+00
Izx Izy Izz 0.0000000e+00 0.0000000e+00 2.7832753e+05
PRINCIPAL MOMENTS OF INERTIA: (KILOGRAM * MM^2)
I1 I2 I3 2.7832726e+05 2.7832767e+05 5.3283652e+05
STOCK TIRE
VOLUME = 8.4822438e+06 MM^3
SURFACE AREA = 2.7036586e+06 MM^2
DENSITY = 5.0000000e-07 KILOGRAM / MM^3
MASS = 4.2411219e+00 KILOGRAM
CENTER OF GRAVITY with respect to _TIRE_TEST coordinate frame:
X Y Z 0.0000000e+00 0.0000000e+00 0.0000000e+00 MM
INERTIA with respect to _TIRE_TEST coordinate frame: (KILOGRAM * MM^2)
INERTIA TENSOR:
Ixx Ixy Ixz 1.0656730e+06 0.0000000e+00 0.0000000e+00
Iyx Iyy Iyz 0.0000000e+00 5.5665481e+05 0.0000000e+00
Izx Izy Izz 0.0000000e+00 0.0000000e+00 5.5665506e+05
INERTIA at CENTER OF GRAVITY with respect to _TIRE_TEST coordinate frame: (KILOGRAM * MM^2)
INERTIA TENSOR:
Ixx Ixy Ixz 1.0656730e+06 0.0000000e+00 0.0000000e+00
Iyx Iyy Iyz 0.0000000e+00 5.5665481e+05 0.0000000e+00
Izx Izy Izz 0.0000000e+00 0.0000000e+00 5.5665506e+05
PRINCIPAL MOMENTS OF INERTIA: (KILOGRAM * MM^2)
I1 I2 I3 5.5665452e+05 5.5665535e+05 1.0656730e+06
I'm sure you know all about rotational inertia and some people claim that 1lb of rotational mass ='s 5 to 7 lbs of static weight, so by me saving anywhere from 5 to 7 lbs of rotational mass, that ='s quite a few burritos.
If anyone else wants to explain this more feel free, I am digging through some old info and will try to correlate this back to a HP savings, but I might give up before I do.
Jeff
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