sdt354
Well-Known Member
+1 to what Max Midnight said. The starter will just draw what it needs. Depending on load.You can have not enough,but never too much battery capacity.
Steve-o
Steve-o
Last edited:
Hello, I did replace the referenced parts. But I did not use a gasket. I used red permatex. The last time I replaced my starter clutch I sheared off my crank woodruff key and I did not use a gasket then. Maybe that is my problem. I may be getting a bind. I am going to have to get back into it and this time use a gasket. I am also seriously thinking about spot mig welding the allen bolts. I hope this Heavy Duty starter clutch is heavy duty. It just pisses me off that this Yamaha starter clutch is such a bogus design. Thanks for the ideas.I would have thought that the battery would only supply what the starter wanted?
Mr Sufidancer, did you replace all of the components in the starter clutch assembly i.e. #7 on the parts fische?
Alternatively, have you used silicon sealer rather than a gasket as this can cause the assembly to bind.
You aren't the first! Read this.
+1 to what Max Midnight said. The starter will just draw what it needs. Depending on load.You can have not enough,but never too much battery capacity.
Steve-o
Yes, and no.
Series wound or permanent magnet DC motors have an enormous current requirement initially. You are assuming that the battery can maintain 12v when the starter is engaged, it cannot.
The starter will draw what it needs, but what it gets depends on the resistance of the wiring and the internal resistance of the battery. The initial inrush of current will be higher when the resistance is lower. A bigger battery has lower internal resistance.
Put another way, no battery and wiring combination will be able to maintain 12v at the starter terminals when the starter is energized, the current flow is just too high. If you put a scope on the battery when the starter is engaged, you would see a momentary dip in voltage to 6 or 8 volts or even lower. The larger the battery the less the voltage will drop resulting in more current through the starter. This will give the starter more torque, especially initial torque.
That may or may not make the starter clutches fail more often. I simply offered it as a possibility.
Yes, and no.
Series wound or permanent magnet DC motors have an enormous current requirement initially. You are assuming that the battery can maintain 12v when the starter is engaged, it cannot.
The starter will draw what it needs, but what it gets depends on the resistance of the wiring and the internal resistance of the battery. The initial inrush of current will be higher when the resistance is lower. A bigger battery has lower internal resistance.
Put another way, no battery and wiring combination will be able to maintain 12v at the starter terminals when the starter is energized, the current flow is just too high. If you put a scope on the battery when the starter is engaged, you would see a momentary dip in voltage to 6 or 8 volts or even lower. The larger the battery the less the voltage will drop resulting in more current through the starter. This will give the starter more torque, especially initial torque.
That may or may not make the starter clutches fail more often. I simply offered it as a possibility.
I do not agree entirely. The bigger the battery the higher the CCAs or for layman the cranking power which in this case talking electronically the current. The torque rating for the starter cannot be improved by means of using a truck sized 12v battery. The starter draws what it needs to achieve that torque so as long as the battery and wires can deliver the flow of current requested. That's why a weak battery may not be able to crank the engine as current is not enough. A battery can read 12v and still may be damaged by not being able to deliver rated CCAs. The drop in voltage while cranking is a consequence of the rush of current to the user. Still it should not drop below mid 10s or else ignition would fail by causing misfire and killing engine. Usually a battery that reads 12v but drops below that number will not be able to crank the engine as the CCAS will be lower than its rating due to damage to the cells.Yes, and no.
Series wound or permanent magnet DC motors have an enormous current requirement initially. You are assuming that the battery can maintain 12v when the starter is engaged, it cannot.
The starter will draw what it needs, but what it gets depends on the resistance of the wiring and the internal resistance of the battery. The initial inrush of current will be higher when the resistance is lower. A bigger battery has lower internal resistance.
Put another way, no battery and wiring combination will be able to maintain 12v at the starter terminals when the starter is energized, the current flow is just too high. If you put a scope on the battery when the starter is engaged, you would see a momentary dip in voltage to 6 or 8 volts or even lower. The larger the battery the less the voltage will drop resulting in more current through the starter. This will give the starter more torque, especially initial torque.
That may or may not make the starter clutches fail more often. I simply offered it as a possibility.
Enter your email address to join: